Normality satisfies transfer condition

This article gives the statement, and possibly proof, of a subgroup property satisfying a subgroup metaproperty
View all subgroup metaproperty satisfactions | View all subgroup metaproperty dissatisfactions |Get help on looking up metaproperty (dis)satisfactions for subgroup properties
|

Property "Page" (as page type) with input value "{{{property}}}" contains invalid characters or is incomplete and therefore can cause unexpected results during a query or annotation process.Property "Page" (as page type) with input value "{{{metaproperty}}}" contains invalid characters or is incomplete and therefore can cause unexpected results during a query or annotation process.

This article gives the statement, and possibly proof, of a basic fact in group theory.
View a complete list of basic facts in group theory
VIEW FACTS USING THIS: directly | directly or indirectly, upto two steps | directly or indirectly, upto three steps|
VIEW: Survey articles about this

Statement

Verbal statement

If a subgroup is normal in the group, its intersection with any other subgroup is normal in that subgroup.

Symbolic statement

Let $H\leq G$ be a normal subgroup and let $K$ be any subgroup of $G$. Then, $H\cap K\triangleleft K$.

Property-theoretic statement

The subgroup property of being normal satisfies the transfer condition.

Definitions used

Normal subgroup

A subgroup $H$ of a group $G$ is said to be normal if for any $g\in G$ and $h\in H$, $ghg^{-1}\in H$.

Transfer condition

A subgroup property $p$ is said to satisfy transfer condition if whenever $H,K$ are subgroups of $G$ and $H$ has property $p$ in $G$, $H\cap K$ has property $p$ in $K$.

Related facts

Further facts

• Second isomorphism theorem: This result equates the quotient of the non-normal subgroup, by the intersection, with the quotient of the product of subgroups, by the normal subgroup. Specifically, it states that if $H$ is normal in $G$ and $K$ is any subgroup of $G$, we have $H/(H\cap K)\cong HK/K$.

Related metaproperties satisfied by normality

• Normality satisfies intermediate subgroup condition: The intermediate subgroup condition is weaker. It says that if $H\leq K\leq G$ are subgroups are $H$ is normal in $G$, then $H$ is normal in $K$.
• Normality satisfies inverse image condition: The inverse image condition is stronger. It says that the inverse image of a normal subgroup under a homomorphism is normal.

Other metaproperties satisfied by normality, that are somewhat related:

• Normality satisfies image condition: The image of a normal subgroup under a surjective homomorphism is normal in the image.
• Normality is upper join-closed

Transfer condition for other subgroup properties

• Subnormality satisfies transfer condition: This follows directly from the fact that normality satisfies the transfer condition, and the fact that transfer condition is subordination-closed.
• Permutability satisfies transfer condition

Analogues in other algebraic structure

• Ideal property satisfies transfer condition in Lie rings

Proof

Hands-on proof

Given: A group $G$, a normal subgroup $H\triangleleft G$ and a subgroup $K\leq G$

To prove: $H\cap K\triangleleft K$. In other words, we need to prove that given any $g\in K$ and $h\in H\cap K$, $ghg^{-1}\in H\cap K$.

Proof: Since $h\in H\cap K$, we in particular have $h\in H$. Since $H\triangleleft G$ (viz $H$ is normal in $G$), $ghg^{-1}\in H$.

But we also have that $g\in K$ and $h\in K$. Since $K$ is a subgroup, $ghg^{-1}\in K$.

Combining these two facts, $ghg^{-1}\in H\cap K$.

References

Textbook references

• Abstract Algebra by David S. Dummit and Richard M. Foote, 10-digit ISBN 0471433349, 13-digit ISBN 978-0471433347, ^{More info}, Page 88, Exercise 24
• Topics in Algebra by I. N. Herstein, ^{More info}, Page 53, Problem 5