Normal Sylow satisfies transfer condition

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This article gives the statement, and possibly proof, of a subgroup property (i.e., normal Sylow subgroup) satisfying a subgroup metaproperty (i.e., transfer condition)
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Statement

Statement with symbols

Suppose H is a normal Sylow subgroup of a finite group G and KG is any subgroup. Then HK is a normal Sylow subgroup of K.

Related facts

More on transfer condition for normal and Sylow subgroups

Intersecting a normal subgroup with a Sylow subgroup

  • Equivalence of definitions of Sylow subgroup of normal subgroup: This states that a subgroup that is the intersection of a Sylow subgroup and a normal subgroup is a Sylow subgroup of the normal subgroup. Conversely, a subgroup expressible as a Sylow subgroup of a normal subgroup is expressible as an intersection of the normal subgroup with a Sylow subgroup of the whole group.

Facts used

  1. Second isomorphism theorem
  2. Lagrange's theorem

Proof

Given: A finite group G, a normal Sylow subgroup H, and a subgroup KG.

To prove: HK is a normal Sylow subgroup of K.

Proof: By the second isomorphism theorem, HK is normal in K, and we have:

K/(HK)HK/H.

Here, HK is a subgroup of G. Since G/H has order relatively prime to p, so does HK/H (by fact (2)). Thus, K/(HK) has order relatively prime to p, so [K:HK] is relatively prime to p. Thus, HK is a normal p-subgroup of K with index relatively prime to p, and is thus a normal p-Sylow subgroup of K.

References

Textbook references

  • Abstract Algebra by David S. Dummit and Richard M. Foote, 10-digit ISBN 0471433349, 13-digit ISBN 978-0471433347, More info, Page 147, Exercise 32, Section 4.5 (Sylow's theorem)