Normality satisfies transfer condition
From Groupprops
This article gives the statement, and possibly proof, of a subgroup property satisfying a subgroup metaproperty
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This article gives the statement, and possibly proof, of a basic fact in group theory.
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Statement
Verbal statement
If a subgroup is normal in the group, its intersection with any other subgroup is normal in that subgroup.
Symbolic statement
Let
be a normal subgroup and let K be any subgroup of G. Then,
.
Property-theoretic statement
The subgroup property of being normal satisfies the transfer condition.
Definitions used
Normal subgroup
A subgroup H of a group G is said to be normal if for any
and
,
.
Transfer condition
A subgroup property p is said to satisfy transfer condition if whenever H,K are subgroups of G and H has property p in G,
has property p in K.
Related facts
Further facts
- Second isomorphism theorem: This result equates the quotient of the non-normal subgroup, by the intersection, with the quotient of the product of subgroups, by the normal subgroup. Specifically, it states that if H is normal in G and K is any subgroup of G, we have
.
Related metaproperties satisfied by normality
- Normality satisfies intermediate subgroup condition: The intermediate subgroup condition is weaker. It says that if
are subgroups are H is normal in G, then H is normal in K.
- Normality satisfies inverse image condition: The inverse image condition is stronger. It says that the inverse image of a normal subgroup under a homomorphism is normal.
Other metaproperties satisfied by normality, that are somewhat related:
- Normality satisfies image condition: The image of a normal subgroup under a surjective homomorphism is normal in the image.
- Normality is upper join-closed
Transfer condition for other subgroup properties
- Subnormality satisfies transfer condition: This follows directly from the fact that normality satisfies the transfer condition, and the fact that transfer condition is subordination-closed.
- Permutability satisfies transfer condition
Analogues in other algebraic structure
Proof
Hands-on proof
Given: A group G, a normal subgroup
and a subgroup
To prove:
. In other words, we need to prove that given any
and
,
.
Proof: Since
, we in particular have
. Since
(viz H is normal in G),
.
But we also have that
and
. Since K is a subgroup,
.
Combining these two facts,
.
References
Textbook references
- Abstract Algebra by David S. Dummit and Richard M. Foote, 10-digit ISBN 0471433349, 13-digit ISBN 978-0471433347, More info, Page 88, Exercise 24
- Topics in Algebra by I. N. Herstein, More info, Page 53, Problem 5
| Page class | Fact + |
| Referenced in | Book:DummitFoote (?, ?, ?) +, and Book:Herstein (?, ?, ?) + |
| Stated in | Book:DummitFoote (?, ?, ?) +, and Book:Herstein (?, ?, ?) + |
| Stronger than | Normality satisfies intermediate subgroup condition + |
| Weaker than | Normality satisfies inverse image condition + |