Permutable implies subnormal in finite

This article gives the statement and possibly, proof, of an implication relation between two subgroup properties, when the big group is a finite group. That is, it states that in a Finite group (?), every subgroup satisfying the first subgroup property (i.e., Permutable subgroup (?)) must also satisfy the second subgroup property (i.e., Subnormal subgroup (?)). In other words, every permutable subgroup of finite group is a subnormal subgroup of finite group.
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Statement

Any permutable subgroup of a finite group is a subnormal subgroup. In particular, it is a permutable subnormal subgroup.

Proof

Given: A finite group $G$, a permutable subgroup $H$ of $G$.

To prove: $H$ is subnormal in $G$.

Proof: We prove this by induction on the order of $G$.

If $H = G$, we are done. Otherwise:

1. Let $K$ be a maximal element among the proper permutable subgroups of $G$ containing $H$. By fact (1), $K$ is normal in $G$.
2. By fact (2), $H$ is permutable in $K$, so induction on the order yields that $H$ is subnormal in $K$.
3. Thus, $H$ is subnormal in $K$ which is normal in $G$, so $H$ is subnormal in $G$.