Characteristic not implies sub-(isomorph-normal characteristic) in finite
This article gives the statement and possibly, proof, of a non-implication relation between two subgroup properties, when the big group is a finite group. That is, it states that in a finite group, every subgroup satisfying the first subgroup property (i.e., characteristic subgroup) need not satisfy the second subgroup property (i.e., sub-(isomorph-normal characteristic) subgroup)
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We can have a finite group and a characteristic subgroup of such that is not sub-(isomorph-normal characteristic) in . In other words, there is no ascending chain of subgroups from to such that each member is an isomorph-normal characteristic subgroup of its successor.
- Characteristic not implies sub-isomorph-free in finite
- Characteristic not implies isomorph-free in finite
The center of a non-abelian group of odd prime cube order
Further information: Prime-cube order group:U3p
Let be an odd prime. Let be the non-abelian group of order and exponent . Let be the center of . Then, we have:
- is characteristic in .
- is not sub-(isomorph-normal characteristic) in : In fact, no proper subgroup of containing is isomorph-normal and characteristic. itself is not isomorph-normal, because there are other cyclic groups of order . Moreover, is a maximal characteristic subgroup of , so there is no other possibility.