Statement
Suppose
are distinct primes. Suppose
is an elementary abelian
-group, and
is an abelian
-group that is not cyclic. Let
be an enumeration of the non-identity elements of
. Then, we have:
.
where
denotes the set of fixed points in
of the automorphism
.
Related facts
Generalizations
- Centralizer product theorem: The same result, except that
is now an arbitrary
-group, rather than an elementary abelian group.
Facts used
- Maschke's averaging lemma
Proof
Given: Primes
. An elementary abelian
-group
, a non-cyclic abelian
-subgroup
of
.
are the non-identity elements of
.
To prove:
.
Proof:
- By fact (1), viewing
as a vector space over the field of
elements and
as a group acting on this vector space, we can decompose
as a direct sum of irreducible
-modules, say
.
- Let
be the pointwise stabilizer of
in
. Then,
is cyclic:
is an abelian group of automorphisms of the vector space
, and
is irreducible. This forces
to be cyclic.
- Each
is a nontrivial subgroup of
: This follows from the previous step and the fact that
isn't cyclic.
- For each
, pick a non-identity element
of
. Then,
contains
: This follows from the definition of
.
: Each
is contained in
for some non-identity element
. Thus,
is the sum of all
,
ranging over the non-identity elements of
.
Reverting to multiplicative notation yields the result.
References
Textbook references
- Finite Groups by Daniel Gorenstein, ISBN 0821843427, Page 69, Theorem 3.3, Chapter 3, Section 3 (Complete reducibility), More info