Burnside's basis theorem

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Statement

Symbolic statement

Let $P$ be a $p$-group for some prime $p$, and let $\Phi(P)$ denote the Frattini subgroup of $P$. Then, $P/\Phi(P)$ is the largest elementary Abelian quotient of $P$, and hence is a vector space over the prime field $\mathbb{F}_p$.

Burnside's basis theorem states that:

• A subset $S$ of $P$ is a generating set for $P$ iff the image of $S$ in $P/\Phi(P)$ generates $P/\Phi(P)$ as a $\mathbb{F}_p$-vector space.
• A subset $S$ of $P$ is a minimal generating set for $P$ iff the image of $S$ in $P/\Phi(P)$ is a vector space basis for $P/\Phi(P)$.

Related facts

Generalizations

Frattini subgroup is finitely generated implies subset is generating set iff image in Frattini quotient is: If the Frattini subgroup of any group is finitely gnerated, then a subset of the whole group is a generating set iff its image mod the Frattini subgroup is a generating set for the Frattini quotient.

Burnside's basis theorem closely parallels certain formulations, and corollaries, of Nakayama's lemma, which states that generating sets for a module are in correspondence with generating sets for its top, which is its quotient by its Jacobson radical. Here, the Jacobson radical of a module plays the role of the Frattini subgroup, as the set of nongenerators.

Related fact on p-groups

Burnside's theorem on coprime automorphisms and Frattini subgroup

Proof

The proof follows directly from the following two facts:

• Combining a generating set for a normal subgroup, and a set of inverse images (via the quotient map) of the quotient group gives us a generating set for the quotient group
• Any element in the Frattini subgroup can be dropped from any generating set.

References

Textbook references

• Abstract Algebra by David S. Dummit and Richard M. Foote, 10-digit ISBN 0471433349, 13-digit ISBN 978-0471433347, ^{More info}, Exercise 26(a), Page 199 (Section 6.2)