Left transiter of normal is characteristic: Difference between revisions

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{{left transiter computation}}
{{left transiter computation}}
 
[[difficulty level::3| ]]
==Statement==
==Statement==


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* [[Left residual of normal by normal Hall is coprime automorphism-invariant normal]]
* [[Left residual of normal by normal Hall is coprime automorphism-invariant normal]]
===Left transiters of other closely related properties===
* [[Characteristic implies left-transitively 2-subnormal]], [[Characteristic implies left-transitively fixed-depth subnormal]]
* [[Subgroup-coprime automorphism-invariant implies left-transitively 2-subnormal]]
* [[Complemented normal is not transitive]]
* [[Left-transitively complemented normal implies characteristic]], [[Characteristic not implies left-transitively complemented normal]]
* [[Left-transitively permutable implies characteristic]]
===Upper hooks and related facts===
* [[Normal upper-hook fully normalized implies characteristic]]: If <math>H \le K \le G</math> are such that <math>H</math> is normal in <math>G</math> and <math>K</math> is [[fully normalized subgroup|fully normalized]] in <math>G</math>, then <math>H</math> is characteristic in <math>K</math>.
* [[Characteristically simple and normal fully normalized implies minimal normal]]


==Facts used==
==Facts used==
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'''Proof''': (1) implies (2) follows from fact (1). We now prove (2) implies (1).
'''Proof''': (1) implies (2) follows from fact (1). We now prove (2) implies (1).


For the group <math>K</math>, let <math>\operatorname{Hol}(K)</math> denote the [[holomorph of a group|holomorph]] of <math>K</math>. <math>\operatorname{Hol}(K)</math> is the semidirect product of <math>K</math> with <math>\operatorname{Aut}(K)</math>. Observe that every automorphism of <math>K</math> lifts to an [[inner automorphism]] of <math>Hol(K)</math>, and further, that <math>K</math> is a normal subgroup of <math>\operatorname{Hol}(K)</math>.
For the group <math>K</math>, let <math>\operatorname{Hol}(K)</math> denote the [[holomorph of a group|holomorph]] of <math>K</math>. <math>\operatorname{Hol}(K)</math> is the semidirect product of <math>K</math> with <math>\operatorname{Aut}(K)</math>. Observe that every automorphism of <math>K</math> lifts to an [[inner automorphism]] of <math>\operatorname{Hol}(K)</math>, and further, that <math>K</math> is a normal subgroup of <math>\operatorname{Hol}(K)</math>.


Now let <math>H</math> be a subgroup of <math>K</math> with the property that whenever <math>K</math> is normal in a group <math>G</math>, so is <math>H</math>. We will show that <math>H</math> is characteristic in <math>K</math>.
Now let <math>H</math> be a subgroup of <math>K</math> with the property that whenever <math>K</math> is normal in a group <math>G</math>, so is <math>H</math>. We will show that <math>H</math> is characteristic in <math>K</math>.


Take <math>G = Hol(K)</math>. Clearly <math>K</math> is normal in <math>G</math>. Now, let <math>\sigma \in \operatorname{Aut}(K)</math>. Clearly, there is an inner automorphism of <math>G</math> whose restriction to <math>K</math> is <math>\sigma</math> (namely, conjugation by the element of <math>\operatorname{Aut}(K)</math> that is <math>\sigma</math>). But <math>H</math> is normal in <math>G</math>, so every inner automorphism of <math>G</math> must leave <math>H</math> invariant, and hence <math>\sigma</math> must leave <math>H</math> invariant. This shows that <math>H</math> is invariant under all automorphisms of <math>K</math>, and hence, is a characteristic subgroup.
Take <math>G = \operatorname{Hol}(K)</math>. Clearly <math>K</math> is normal in <math>G</math>. Now, let <math>\sigma \in \operatorname{Aut}(K)</math>. Clearly, there is an inner automorphism of <math>G</math> whose restriction to <math>K</math> is <math>\sigma</math> (namely, conjugation by the element of <math>\operatorname{Aut}(K)</math> that is <math>\sigma</math>). But <math>H</math> is normal in <math>G</math>, so every inner automorphism of <math>G</math> must leave <math>H</math> invariant, and hence <math>\sigma</math> must leave <math>H</math> invariant. This shows that <math>H</math> is invariant under all automorphisms of <math>K</math>, and hence, is a characteristic subgroup.


===Property-theoretic proof===
===Property-theoretic proof===

Revision as of 17:35, 24 February 2011

Template:Left transiter computation

Statement

Statement with symbols

Let HK be a subgroup. The following are equivalent:

  1. H is a Characteristic subgroup (?) of K
  2. If G is a group containing K such that K is a Normal subgroup (?) of G, then H is also a normal subgroup of G.

Property-theoretic statement

The left transiter of the subgroup property of normality is the subgroup property of characteristicity. In other words:

  • Characteristic * Normal Normal

Every characteristic subgroup of a normal subgroup is normal (the * here is for the composition operator).

  • If p is such that:

p* Normal Normal

Then p Characteristic

Definitions used

Characteristic subgroup

  • Hands-on definition: A subgroup H of a group G is termed characteristic in G if for any automorphism σ of G, σ(H)=H.
  • Definition using function restriction expression: A subgroup H of a group G is termed characteristic in G if it has the following function restriction expression:

Automorphism Automorphism

In other words, every automorphism of G restricts to an automorphism of H.

Normal subgroup

  • Hands-on definition: A subgroup H of a group G is termed normal in G if for every gG, gHg1=H.
  • Definition using function restriction expression: A subgroup H of a group G is termed normal in G if it has the following function restriction expression:

Inner automorphism Automorphism

In other words, every inner automorphism of G restricts to an automorphism of H.

Related facts

Related left residual computations

All these use the fact that inner automorphism to automorphism is right tight for normality.

Some examples with a somewhat different flavor:

Left transiters of other closely related properties

Upper hooks and related facts

Facts used

  1. Characteristic of normal implies normal (used for the more direct part of the proof).
  2. Inner automorphism to automorphism is right tight for normality

Proof

Hands-on proof

Given: A subgroup H of a group K.

To prove: The following are equivalent:

  1. H is characteristic in K.
  2. For every group G in which K is normal, H is normal in G.

Proof: (1) implies (2) follows from fact (1). We now prove (2) implies (1).

For the group K, let Hol(K) denote the holomorph of K. Hol(K) is the semidirect product of K with Aut(K). Observe that every automorphism of K lifts to an inner automorphism of Hol(K), and further, that K is a normal subgroup of Hol(K).

Now let H be a subgroup of K with the property that whenever K is normal in a group G, so is H. We will show that H is characteristic in K.

Take G=Hol(K). Clearly K is normal in G. Now, let σAut(K). Clearly, there is an inner automorphism of G whose restriction to K is σ (namely, conjugation by the element of Aut(K) that is σ). But H is normal in G, so every inner automorphism of G must leave H invariant, and hence σ must leave H invariant. This shows that H is invariant under all automorphisms of K, and hence, is a characteristic subgroup.

Property-theoretic proof

By fact (2), the function restriction expression:

Inner automorphism Automorphism

is a right tight function restriction expression for normality. In other words, for every automorphism of a group, there is a bigger group in which it is normal, such that the automorphism extends to an inner automorphism in that bigger group. Combining this with fact (3), we see that the left transiter of normality is the property:

Automorphism Automorphism

which is indeed the property of being a characteristic subgroup.