# Transitively normal not implies central factor

This article gives the statement and possibly, proof, of a non-implication relation between two subgroup properties. That is, it states that every subgroup satisfying the first subgroup property (i.e., transitively normal subgroup) need not satisfy the second subgroup property (i.e., central factor)
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## Statement

It is possible to have a group $G$ and a transitively normal subgroup $K$ of $G$ (i.e., any normal subgroup $H$ of $K$ is normal in $G$) that is not a central factor of $G$.

## Proof

### Example of the dihedral group

Further information: dihedral group:D8, cyclic maximal subgroup of dihedral group:D8

Consider the dihedral group of order eight: $G := \langle a,x \mid a^4 = x^2 = e, xax = a^{-1} \rangle$.

Suppose $K$ is the cyclic subgroup of order four: $K := \langle a \rangle$.

Then:

• $K$ is a transitively normal subgroup of $G$: $K$ is normal (it has index two in $G$), and its proper subgroups (the trivial subgroup, and the subgroup $\langle a^2 \rangle$) are all normal in $G$ as well.
• $K$ is not a central factor of $G$: Conjugation by $x$ gives an automorphism of $K$ that sends $a$ to $a^{-1}$, and is hence not an inner automorphism of $K$.