N-abelian iff (1-n)-abelian
The idea is to show that the condition for being -abelian on is equivalent to the condition for being -abelian on . Since the inverse map is bijective, varying over all of also varies over all of .
Given: A group , elements such that .
To prove: .Proof: This is straightforward group element manipulation. PLACEHOLDER FOR INFORMATION TO BE FILLED IN: [SHOW MORE]