General semilinear group

Definition

Suppose $K$ is a field and $n$ is a natural number. The general semilinear group of degree $n$ over $K$, denoted $\Gamma L(n,k)$, is defined as the group of all semilinear transformations from a $n$-dimensional vector space over $K$ to itself.

It can also be described explicitly as an external semidirect product of the general linear group $GL(n,K)$ by the automorphism group of $K$ as a field (acting entry-wise on the matrices), i.e.:

$\Gamma L(n,K) = GL(n,K) \rtimes \operatorname{Aut}(K)$

Suppose $k$ is the prime subfield of $K$ and suppose that $K$ is a Galois extension over $k$ (this is always true for $K$ a finite field). Then, $\operatorname{Aut}(K) = \operatorname{Gal}(K/k)$ and we can rewrite the group as:

$\Gamma L(n,K) = GL(n,K) \rtimes \operatorname{Gal}(K/k)$

where the action of $\operatorname{Gal}(K/k)$ on $GL(n,K)$ is obtained by inducing the corresponding Galois automorphism on each matrix entry.

If $q$ is a prime power, we denote by $\Gamma L(n,q)$ the group $\Gamma L(n,\mathbb{F}_q)$ where $\mathbb{F}_q$ is the (unique up to isomorphism) field of size $q$.

Arithmetic functions

For a finite field

We consider here a field $K = \mathbb{F}_q$ of size $q = p^r$ where $p$ is the field characteristic, so $r$ is a natural number.

The prime subfield is $k = \mathbb{F}_p$, and the extension $K/k$ has degree $r$. The Galois group of the extension thus has size $r$. Note that the Galois group of the extension is always a cyclic group of order $r$ and is generated by the Frobenius automorphism $x \mapsto x^p$.

We are interested in the group $\Gamma L(n,q)$.

Function	Value	Explanation
order	$rq^{\binom{n}{2}}\prod_{i=1}^n (q^i - 1)$	order of semidirect product is product of orders: we multiply the order $r$ of the Galois group with the order of the general linear group.

Particular cases

Finite cases

We consider a field of size $q = p^r$ where $p$ is the underlying prime and field characteristic, and therefore $r$ is the degree of the extension over the prime subfield and also the order of the Galois group.

Note that in the case $r = 1$, the general semilinear group coincides with the general linear group.

$q$ (field size)	$p$ (underlying prime, field characteristic)	$r$ (degree of extension over prime subfield)	$n$	$\Gamma L(n,q)$	order of $\Gamma L(n,q)$
2	2	1	1	trivial group	1
3	3	1	1	cyclic group:Z2	1
4	2	2	1	symmetric group:S3	6
5	5	1	1	cyclic group:Z4	4
7	7	1	1	cyclic group:Z6	6
8	2	3	1	semidirect product of Z7 and Z3	21
2	2	1	2	symmetric group:S3	6
3	3	1	2	general linear group:GL(2,3)	48
4	2	2	2	general semilinear group:GammaL(2,4)	360
5	5	1	2	general linear group:GL(2,5)	480