Degree of irreducible representation need not divide exponent

From Groupprops

Statement

We can have a finite group and an irreducible linear representation of the group over an algebraically closed field of characteristic zero (or more generally over a splitting field), such that the degree of the irreducible representation does not divide the exponent of the group.

This is a non-constraint on the Degrees of irreducible representations (?) of a finite group.

Related facts

Similar facts

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Proof

Example of big extraspecial groups

Consider an extraspecial group of order for any prime . The exponent of this group is either or . On the other hand, it admits a faithful irreducible representation of degree .

For odd primes , we can take an example of an extraspecial group of order and exponent , which admits a faithful irreducible representation of degree .

Example of symmetric group of degree six

Further information: symmetric group:S6, linear representation theory of symmetric group:S6

The symmetric group of degree six has an irreducible representation of degree over the rational numbers, arising from the self-conjugate partition . On the other hand, the exponent of the group is the lcm of the numbers from to , which is , and is not a multiple of .