# Characteristic not implies isomorph-normal in finite group

This article gives the statement and possibly, proof, of a non-implication relation between two subgroup properties, when the big group is a finite group. That is, it states that in a finite group, every subgroup satisfying the first subgroup property (i.e., characteristic subgroup) need not satisfy the second subgroup property (i.e., isomorph-normal subgroup)
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## Statement

### Statement with symbols

It is possible to have a group $G$ and a subgroup $H$ of $G$ such that $H$ is a characteristic subgroup of $G$ but is not isomorph-normal in $G$: there exists a subgroup $K$ of $G$ isomorphic to $H$ that is not normal in $G$.

## Proof

### Example of the dihedral group

Further information: dihedral group:D8

Let $G$ be the dihedral group of order eight, given by: $G = \langle a,x \mid a^4 = x^2 = 1, xax = a^{-1} \rangle$.

Let $H$ be the center of $G$. $H$ is a subgroup of order two generated by $a^2$.

• $H$ is characteristic.
• $H$ is not isomorph-normal: The subgroup $\langle x \rangle$ of $G$ is isomorphic to $H$, but is not normal in $G$, because conjugation by $a$ sends it to the subgroup $\langle a^2x \rangle$.