Characteristic of normal implies normal

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This article describes a computation relating the result of the Composition operator (?) on two known subgroup properties , to another known subgroup property
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Statement

Property-theoretic statement

Characteristic * Normal ≤ Normal

Verbal statement

Every characteristic subgroup of a normal subgroup is normal.

Symbolic statement

Let H≤K≤G such that H is characteristic in K and K is normal in G, then H is normal in G.

Related facts

Proof

Hands-on proof

Given groups H≤K≤G such that H is characteristic in K and K is normal in G. We need to show that for any g∈G, the map cg:x↦gxg−1 takes H to within itself.

First, notice that since K◃G, cg(x)∈K for every x∈K. Thus, cg restricts to a function from K to K. Since this function arises by restricting an automorphism of G, it is an endomorphism of K.

Further, since cg−1∘cg is the identity map, and K is invariant under both, the restriction of cg to H is actually an invertible endomorphism, viz an automorphism. Call this automorphism σ.

Since H is characteristic in K, σ takes H to within itself. But since σ is the restriction of cg to K in the first place, we conclude that cg in fact takes H to itself.

Using the function restriction formalism

In terms of the function restriction formalism:

Inner automorphism → Automorphism

Automorphism → Automorphism

We now use the composition rule for function restriction to observe that the composition of characteristic and normal implies the property:

Inner automorphism → Automorphism

Which is again the subgroup property of normality.