Focal subgroup theorem

From Groupprops
Revision as of 21:08, 9 February 2009 by Vipul (talk | contribs)

This is a purely group-theoretic statement whose proof requires the use of some more advanced machinery, namely that from: linear representation theory

This article gives the statement and possibly, proof, of an implication relation between two subgroup properties. That is, it states that every subgroup satisfying the first subgroup property (i.e., Sylow subgroup) must also satisfy the second subgroup property (i.e., subgroup whose focal subgroup equals its intersection with the commutator subgroup)
View all subgroup property implications | View all subgroup property non-implications
Get more facts about Sylow subgroup|Get more facts about subgroup whose focal subgroup equals its intersection with the commutator subgroup

Statement

Let P be a p-Sylow subgroup of a finite group G and let:

P0=xy1x,yP,gG,gxg1=y.

In other words, P0 is the focal subgroup of P in G.

Then:

PG=P0

In other words, P is a subgroup whose focal subgroup equals its intersection with the commutator subgroup.

Proof

Given: A finite group G, a p-Sylow subgroup P. P0 is the focal subgroup of P, defined by:

P0=xy1x,yP,gG,gxg1=y.

Further, we have:

G=[G,G]=xy1x,yG,gG,gxg1=y.

To prove: P0=PG.


Initial observation

First, note that PP0PG. The first inclusion is because every commutator of elements in P is contained inside the generating set for P0, and the second inclusion is because every element in the given generating set for P0 is both in P and in G0.

Since P0 contains P, P/P0 is an Abelian group.

Main proof

Let p1,p2,,pm be the distinct prime divisors of |G| with p=p1. For each pi, pick a pi-Sylow subgroup Pi such that P1=P.

Now, any gG can be expressed as a product g=g1g2gm where each gi is conjugate to some hiPi and the gi commute pairwise. If g1 is also conjugate to h1P1 then h1h1'1P0.

Let λ be a linear character of P whose kernel contains P0. We claim that the function:

θ(g)=λ(h1)

where h1 is as described above, is well-defined. The reason is that if h1 and h1 are two possibles, then λ(h1h1'1)=1 and hence λ(h1)=λ(h1).

Clearly, θ is a class function on G. Then by the characterization of linear characters lemma, we conclude that θ is a linear character of G. Further θ extends λ, viz the restriction of θ to P is λ.

Thus, given any linear character on P/P0, we get a linear character on G extending it. In particular, this means that for any element in PP0, there is a linear character on G that is not 1 at that element. Thus, that element cannot lie in G, and hence P0=PG.

References

Journal references

Textbook references

  • Finite Groups by Daniel Gorenstein, ISBN 0821843427, More info, Page 250, Theorem 3.4, Section 7.3 (Transfer and the focal subgroup)