Nilpotency-forcing number: Difference between revisions
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==Definition== | ==Definition== | ||
A natural number <math>n</math> is said to be '''nilpotency-forcing''' or '''nilpotence-forcing''' if the following equivalent conditions hold: | |||
# Every group of order <math>n</math> is [[nilpotent group|nilpotent]] | |||
# Every group of order <math>n</math> is a direct product of its Sylow subgroups | |||
# Every prime divisor of <math>n</math> is [[Sylow-direct prime divisor|Sylow-direct]] | |||
# Every prime divisor of <math>n</math> is [[Sylow-unique prime divisor|Sylow-unique]] | |||
# Suppose <math>p_i, p_j</math> are prime divisors of <math>n</math> and <math>p_j^{k_j}</math> is the largest power of <math>p_j</math> dividing <math>n</math>. Then, the order of <math>p_j</math> modulo <math>p_i</math> exceeds <math>k_j</math>. In other words, <math>p_i</math> does not divide <math>p^j^l - 1</math> for <math>1 \le l \le k_j</math>. | |||
For proof of the equivalence of definitions, see [[classification of nilpotency-forcing numbers]]. | |||
==Relation with other properties== | ==Relation with other properties== | ||
Revision as of 20:17, 20 June 2016
This article defines a property that can be evaluated for natural numbers
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Definition
A natural number is said to be nilpotency-forcing or nilpotence-forcing if the following equivalent conditions hold:
- Every group of order is nilpotent
- Every group of order is a direct product of its Sylow subgroups
- Every prime divisor of is Sylow-direct
- Every prime divisor of is Sylow-unique
- Suppose are prime divisors of and is the largest power of dividing . Then, the order of modulo exceeds . In other words, does not divide for .
For proof of the equivalence of definitions, see classification of nilpotency-forcing numbers.