Local powering-invariant subgroup containing the center is intermediately local powering-invariant in nilpotent group: Difference between revisions
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! Step no. !! Assertion/construction !! Facts used !! Given data used !! Previous steps used !! Explanation | ! Step no. !! Assertion/construction !! Facts used !! Given data used !! Previous steps used !! Explanation | ||
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| 1 || <math>Z(G) \le K</math>. || || <math>Z(G) \le H, H \le K</math> | | 1 || <math>Z(G) \le K</math>. || || <math>Z(G) \le H, H \le K</math> || || given-direct | ||
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| 2 || <math>K</math> is nilpotent. || Fact (3) || <math>G</math> is nilpotent, <math>K \le G</math> || || Given-fact direct | | 2 || <math>K</math> is nilpotent. || Fact (3) || <math>G</math> is nilpotent, <math>K \le G</math> || || Given-fact direct | ||
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| 3 || <math>K</math> is <math>p</math>-torsion-free. || Fact (2) || <math>h \in K</math> has a unique <math>p^{th}</math> root in <math>K</math> | | 3 || <math>K</math> is <math>p</math>-torsion-free. || Fact (2) || <math>h \in K</math> has a unique <math>p^{th}</math> root in <math>K</math> || || We use the equivalence (3) implies (1) within the multi-part equivalence of Fact (2). | ||
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| 4 || <math>Z(G)</math> is <math>p</math>-torsion-free. || Fact (1) || || Steps (1), (3) || Step-fact combination direct | | 4 || <math>Z(G)</math> is <math>p</math>-torsion-free. || Fact (1) || || Steps (1), (3) || Step-fact combination direct | ||
Revision as of 01:43, 3 July 2026
Statement
Suppose is a nilpotent group and is a subgroup containing the center of that is also a local powering-invariant subgroup of . Then, is an intermediately local powering-invariant subgroup of . Explicitly, suppose is a subgroup of containing . Then, is a local powering-invariant subgroup of .
Related facts
Facts used
- Torsion-freeness for a prime is subgroup-closed
- Equivalence of definitions of nilpotent group that is torsion-free for a set of primes
- Nilpotency is subgroup-closed
Proof
Given: A nilpotent group , a subgroup of that is local powering-invariant and such that where is the center of . A subgroup of containing . A prime number and an element such that there is a unique element satisfying .
To prove: There exists a unique element such that .
Proof:
| Step no. | Assertion/construction | Facts used | Given data used | Previous steps used | Explanation |
|---|---|---|---|---|---|
| 1 | . | given-direct | |||
| 2 | is nilpotent. | Fact (3) | is nilpotent, | Given-fact direct | |
| 3 | is -torsion-free. | Fact (2) | has a unique root in | We use the equivalence (3) implies (1) within the multi-part equivalence of Fact (2). | |
| 4 | is -torsion-free. | Fact (1) | Steps (1), (3) | Step-fact combination direct | |
| 5 | The map is injective in . | Fact (2) | is nilpotent | Step (4) | Step-fact combination direct (specifically, we want to use the implication from (4) to (1) in the multi-part equivalence of Fact (2)) |
| 6 | The element is the unique root of in all of . | satisfies . | Step (5) | given-step direct | |
| 7 | The element of Step (6) is in . | is local powering-invariant in . | Step (6) | Step-given combination direct. |