Jordan-Holder theorem: Difference between revisions

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(New page: {{semibasic fact}} ==Statement== Suppose <math>G</math> is a fact about::group of finite composition length. In other words, <math>G</math> has a fact about::composition series o...)
 
 
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==Statement==
==Statement==


Suppose <math>G</math> is a [[fact about::group of finite composition length]]. In other words, <math>G</math> has a [[fact about::composition series]] of finite length <math>l</math>:
Suppose <math>G</math> is a [[group of finite composition length]]. In other words, <math>G</math> has a [[composition series]] of finite length <math>l</math>:


<math>\{ e \} = N_0 < N_1 < N_2 < \dots < N_l = G</math>
<math>\{ e \} = N_0 \triangleleft N_1 \triangleleft N_2 \triangleleft \dots \triangleleft N_l = G</math>


where each <math>N_{i-1}</math> is a [[proper normal subgroup]] of <math>N_i</math> and <math>N_i/N_{i-1}</math> is a [[simple group]]. Then, the following are true:
where each <math>N_{i-1}</math> is a [[proper normal subgroup]] of <math>N_i</math> and <math>N_i/N_{i-1}</math> is a [[simple group]]. Then, the following are true:

Latest revision as of 00:59, 14 June 2024

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Statement

Suppose G is a group of finite composition length. In other words, G has a composition series of finite length l:

{e}=N0N1N2Nl=G

where each Ni1 is a proper normal subgroup of Ni and Ni/Ni1 is a simple group. Then, the following are true:

  1. Any composition series for G has length l.
  2. The list of composition factors is the same for any two composition series. In other words, if Ni form one composition series and Mi form another, then for any simple group S, the number of i for which S is isomorphic to Ni/Ni1 equals the number of i for which S is isomorphic to Mi/Mi1.

Related facts

Some other related facts: