Center not is surjective endomorphism-balanced: Difference between revisions
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{{sdf subgroup property dissatisfaction| | {{sdf subgroup property dissatisfaction| | ||
sdf = center| | sdf = center| | ||
property = | property = surjective endomorphism-balanced subgroup}} | ||
==Statement== | ==Statement== | ||
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==Related facts== | ==Related facts== | ||
===Other proofs of similar subgroup-defining functions not being | ===Other proofs of similar subgroup-defining functions not being surjective endomorphism-balanced=== | ||
* [[Baer norm not is | * [[Baer norm not is surjective endomorphism-balanced]] | ||
* [[Wielandt subgroup not is | * [[Wielandt subgroup not is surjective endomorphism-balanced]] | ||
===Proofs of similar subgroup-defining functions being strictly characteristic=== | ===Proofs of similar subgroup-defining functions being strictly characteristic=== | ||
Latest revision as of 23:45, 10 August 2009
This article gives the statement, and possibly proof, of the fact that for a group, the subgroup obtained by applying a given subgroup-defining function (i.e., center) does not always satisfy a particular subgroup property (i.e., surjective endomorphism-balanced subgroup)
View subgroup property satisfactions for subgroup-defining functionsView subgroup property dissatisfactions for subgroup-defining functions
Statement
Statement with symbols
It is possible to have a group and a surjective endomorphism of such that the restriction of to the center is not surjective as an endomorphism of .
Related facts
Other proofs of similar subgroup-defining functions not being surjective endomorphism-balanced
- Baer norm not is surjective endomorphism-balanced
- Wielandt subgroup not is surjective endomorphism-balanced
Proofs of similar subgroup-defining functions being strictly characteristic
- Center is strictly characteristic
- Baer norm is strictly characteristic
- Wielandt subgroup is strictly characteristic
Facts used
- Isomorphic to inner automorphism group not implies centerless: We can have a group such that the center is nontrivial, but there is an isomorphism between and .
Proof
Proof using fact (1)
Let be an example group for fact (1). Let and the quotient map and be an isomorphism. Then, is a surjective endomorphism of . On the other hand, the restriction of to is the trivial map, which is not surjective by the assumption that is a nontrivial group.