Finite NIPC theorem
From Groupprops
This fact is related to: NIPC conjecture
View other facts related to NIPC conjecture View terms related to NIPC conjecture |
Contents |
Statement
Suppose G is a finite group and H is a normal subgroup of G. Then, there exists a finite group K and a surjective homomorphism
such that both the kernel of ρ and ρ − 1(H) are characteristic subgroups of K.
Related facts
- Finite NPC theorem
- No nontrivial abelian normal p-subgroup for some prime p implies every normal subgroup is strongly image-potentially characteristic
Generalizations
Facts used
- Cayley's theorem
- Normal Hall implies characteristic
- Characteristicity is centralizer-closed
- Quotient group acts on abelian normal subgroup
Proof
Given: A finite group G, a normal subgroup H of G.
To prove: There exists a group K and a surjective homomorphism
such that the kernel of ρ and ρ − 1(H) are both characteristic in K.
Proof:
- Let L = G / H. Suppose p is a prime not dividing the order of G. By fact (1), L is a subgroup of the symmetric group
, which in turn can be embedded in the general linear group GL(n,p) where n = | L | . Thus, L has a faithful representation on a vector space V of dimension n over the prime field of order p.
- Since L = G / H, a faithful representation of L on V gives a representation of G on V whose kernel is H. Let K be the semidirect product
for this action, with
the quotient map.
- V (the kernel of ρ) is characteristic in K: In fact, V is a normal p-Sylow subgroup, and hence is characteristic (fact (2)) (it can be defined as the set of all elements whose order is a power of p).
- CK(V) is characteristic in K: This follows from the previous step and fact (3).
-
: Since V is abelian, the quotient group K / V acts on V (fact (4)); in particular, any two elements in the same coset of V have the same action by conjugation on V. Thus, the centralizer of V comprises those cosets of V for which the corresponding element of G fixes V. This is precisely the cosets of elements of H. Thus,
. Since the action is trivial,
.
The last two steps show that ρ − 1(H) is characteristic in K, while step (3) shows that the kernel of ρ is characteristic in K. This completes the proof.