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Schur multiplier of Z-group is trivial

This article gives the statement and possibly, proof, of an implication relation between two group properties. That is, it states that every group satisfying the first group property (i.e., Z-group) must also satisfy the second group property (i.e., Schur-trivial group)
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Suppose G is a Z-group, i.e., G is a finite group such that every Sylow subgroup of G is a cyclic group (and in particular, a finite cyclic group). Then, G is a Schur-trivial group: the Schur multiplier of G is the trivial group.

Facts used


The proof follows directly from facts (1) and (2).