Inverse map is automorphism iff abelian
This article describes an easy-to-prove fact about basic notions in group theory, that is not very well-known or important in itself
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This article gives a result about how information about the structure of the automorphism group of a group (abstractly, or in action) can control the structure of the group
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Statement
The following are equivalent for a group:
- The map sending every element to its inverse, is an endomorphism
- The map sending every element to its inverse, is an automorphism
- The group is abelian
The equivalence of (1) and (2) is direct from the fact that the inverse map is bijective.
Related facts
Similar facts for other power maps
- Square map is endomorphism iff abelian
- Cube map is endomorphism iff abelian (if order is not a multiple of 3), cube map is automorphism implies abelian
- kth power map is bijective iff k is relatively prime to the order
- nth power map is endomorphism iff abelian (if order is relatively prime to n(n-1))
- abelian implies universal power map is endomorphism
- Frattini-in-center odd-order p-group implies (p plus 1)-power map is automorphism
- Frattini-in-center odd-order p-group implies p-power map is endomorphism
Applications
- Fixed-point-free involution on finite group is inverse map
- Automorphism sends more than three-fourths of elements to inverses implies abelian
Related facts for other algebraic structures
- Negation map is automorphism iff abelian for Lie ring
- Inverse map is automorphism not implies abelian for loop
Proof
Given: A group
To prove: is Abelian iff the map is an automorphism.
Proof: The following fact is true:
Thus, we see that:
commute
Since the inverse map is a bijection, this tells us that the above is a homomorphism iff any two elements commute.
Textbook references
- Algebra by Michael Artin, ISBN 0130047635, 13-digit ISBN 978-0130047632, More info, Page 71, Exercise 12(b) of Section 3 (Isomorphisms)