Every group is a quotient of a free group

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Statement

Suppose G is a group and S is a generating set for G. Then, G is isomorphic to a Quotient group (?) of a Free group (?) of rank equal to the cardinality of S.

More specifically, we let T be a set in bijection with S, and F(T) be the free group on T, and we can construct a surjective homomorphism:

F(T)G

which is the unique each element in T to its image in S under the bijection.

Particular cases

Related facts