4-subnormal not implies finite-conjugate-join-closed subnormal

This article gives the statement and possibly, proof, of a non-implication relation between two subgroup properties. That is, it states that every subgroup satisfying the first subgroup property (i.e., 4-subnormal subgroup) need not satisfy the second subgroup property (i.e., finite-conjugate-join-closed subnormal subgroup)
View a complete list of subgroup property non-implications | View a complete list of subgroup property implications
Get more facts about 4-subnormal subgroup|Get more facts about finite-conjugate-join-closed subnormal subgroup

EXPLORE EXAMPLES YOURSELF: View examples of subgroups satisfying property 4-subnormal subgroup but not finite-conjugate-join-closed subnormal subgroup|View examples of subgroups satisfying property 4-subnormal subgroup and finite-conjugate-join-closed subnormal subgroup