Character orthogonality theorem

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This fact is related to: linear representation theory
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This article describes an orthogonality theorem. View a list of orthogonality theorems

Name

This result is known as the first orthogonality theorem, character orthogonality theorem or row orthogonality theorem.

Statement

Statement over complex numbers

Let G be a finite group and C denote the field of complex numbers. Let z¯ denote the complex conjugate of z. Then, if ρ1 and ρ2 are two inequivalent irreducible linear representations, and χ1 and χ2 are their characters, we have:

gGχ1(g)χ2(g)¯=0

and:

gGχ1(g)χ1(g)=|G|

Statement over complex numbers in terms of inner product of class functions

Consider the space of complex-valued functions GC. This is a C-vector space in a natural way, with basis being the indicator functions of elements of G. Consider the Hermitian inner product on this vector space given by:

f1,f2=1|G|gGf1(g)f2(g)¯

Then, the characters form an orthonormal set of functions with respect to this basis.

Statement over general fields

Let G be a finite group and k a field whose characteristic does not divide the order of G. Let ρ1 and ρ2 be two inequivalent irreducible linear representations of G over k and let χ1 and χ2 denote their characters. Then, the following are true:

gGχ1(g)χ2(g1)=0

And:

gGχ1(g)χ1(g1)=d|G|

where d=1 if the field k is a splitting field for G (for instance, if k is sufficiently large for G, viz., contains all the mth roots of 1 where m is the exponent of G).

When k is not sufficiently large, d is the number of irreducible constituents of χ1 when taken over a splitting field containing k.

Statement over general fields in terms of inner product of class functions

For functions f1,f2:Gk, define the following inner product:

f1,f2=1|G|gGf1(g)f2(g1)

Then, the character orthogonality theorem states that the characters of irreducible linear representations form an orthogonal set of elements, and further, if we are working over a sufficiently large field, they form an orthonormal set.

Note that by Maschke's lemma, the irreducible linear representations are precisely the indecomposable linear representations when the characteristic of k does not divide the order of G, so we can replace irreducible in the above statement with indecomposable.

Consequences