Normal iff potential endomorphism kernel: Difference between revisions

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# <math>H</math> is a [[normal subgroup]] of <math>G</math>.
# <math>H</math> is a [[normal subgroup]] of <math>G</math>.
# There exists a [[group]] <math>K</math> containing <math>G</math> such that <math>H</math> is an [[endomorphism kernel]] in <math>K</math>.
# There exists a [[group]] <math>K</math> containing <math>G</math> such that <math>H</math> is an [[endomorphism kernel]] in <math>K</math>.
==Facts used==
# Endomorphism kernel implies normal
# [[uses::Normality satisfies intermediate subgroup condition]]


==Proof==
==Proof==
===(2) implies (1) (the easy direction)===
If (2) holds, <math>H</math> is a normal subgroup of <math>K</math> by Fact (1). By Fact (2), then, <math>H</math> is also a normal subgroup of <math>G</math>.
===(1) implies (2) (the hard direction)===


Let <math>K</math> be the [[external direct product]] (we could also take the [[restricted external direct product]]) of <math>G</math> and a countably infinite number of copies of <math>G/H</math>, i.e.,:
Let <math>K</math> be the [[external direct product]] (we could also take the [[restricted external direct product]]) of <math>G</math> and a countably infinite number of copies of <math>G/H</math>, i.e.,:

Latest revision as of 19:14, 16 February 2013

This article gives a proof/explanation of the equivalence of multiple definitions for the term normal subgroup
View a complete list of pages giving proofs of equivalence of definitions

Statement

The following are equivalent for a subgroup H in a group G:

  1. H is a normal subgroup of G.
  2. There exists a group K containing G such that H is an endomorphism kernel in K.

Facts used

  1. Endomorphism kernel implies normal
  2. Normality satisfies intermediate subgroup condition

Proof

(2) implies (1) (the easy direction)

If (2) holds, H is a normal subgroup of K by Fact (1). By Fact (2), then, H is also a normal subgroup of G.

(1) implies (2) (the hard direction)

Let K be the external direct product (we could also take the restricted external direct product) of G and a countably infinite number of copies of G/H, i.e.,:

K=G×G/H×G/H×

Identify G with the first direct factor (i.e., treating it as an internal direct product locally) and H with the subgroup H in the first direct factor.

By construction H is the kernel of the endomorphism of K that sends each direct factor to the next, with the first map GG/H being the quotient map by H, and the remaining maps being identity maps. Explicitly, if π:GG/H is the quotient map, the mapping we are talking about is:

(a,g1,g2,,gn,)(e,π(a),g1,g2,,gn1,)

(where e denotes the identity element).