Tour:Inquiry problems one (beginners): Difference between revisions
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The ''nonzero'' reals form a group under multiplication. Zero, however, is not invertible. | The ''nonzero'' reals form a group under multiplication. Zero, however, is not invertible. | ||
Here's one way to try to remedy this. Consider the set <math>\R_\infty = \R \cup \{ \infty \}</math>. Define the following multiplication on <math>\R_\infty</math>: the product of two finite real numbers is their usual product, the product of a nonzero real number with <math>\infty</math> is <math>\infty</math>, the product of <math>\infty</math> and <math>\infty</math> is <math>\infty</math>, and the product of <math>0</math> and <math>\infty</math> is <math>1</math>. | Here's one way to try to remedy this. Consider the set <math>\R_\infty = \R \cup \{ \infty \}</math>. Define the following commutative multiplication on <math>\R_\infty</math>: the product of two finite real numbers is their usual product, the product of a nonzero real number with <math>\infty</math> is <math>\infty</math> (whichever order we multiply them in), the product of <math>\infty</math> and <math>\infty</math> is <math>\infty</math>, and the product of <math>0</math> and <math>\infty</math> is <math>1</math>. | ||
{{quotation|Is <math>\R_\infty</math> a group under multiplication?}} | {{quotation|Is <math>\R_\infty</math> a group under multiplication?}} | ||
Explore the methods you used to prove this result, and what they tell you about the nature of groups. | Explore the methods you used to prove this result, and what they tell you about the nature of groups. | ||
Revision as of 16:46, 25 June 2012
This page is a Inquiry problems page, part of the Groupprops guided tour for beginners (Jump to beginning of tour)
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NEXT SECTION Inquiry problems: Inquiry problems two
General instructions for the tour | Pedagogical notes for the tour | Pedagogical notes for this part
This page lists some problems for thought/inquiry. Many of these problems are aha problems, and they should be obvious at the end of part two.
Adding a point at infinity
The nonzero reals form a group under multiplication. Zero, however, is not invertible.
Here's one way to try to remedy this. Consider the set . Define the following commutative multiplication on : the product of two finite real numbers is their usual product, the product of a nonzero real number with is (whichever order we multiply them in), the product of and is , and the product of and is .
Is
a group under multiplication?
Explore the methods you used to prove this result, and what they tell you about the nature of groups.