Character determines representation in characteristic zero: Difference between revisions
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==Facts used== | ==Facts used== | ||
# [[uses::Character orthogonality theorem]] | |||
# [[uses::Orthogonal projection formula]] | # [[uses::Orthogonal projection formula]] | ||
Revision as of 03:36, 13 July 2011
Statement
Suppose is a finite group and is a field of characteristic zero. Then, the character of any finite-dimensional representation of over completely determines the representation, i.e., no two inequivalent finite-dimensional representations can have the same character.
Related facts
- Character does not determine representation in any prime characteristic: The problem is that we can construct representations whose character is identically zero simply by adding copies of an irreducible representation to itself.