Character orthogonality theorem: Difference between revisions

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===Relation between the Hermitian inner product and the bilinear inner product===
===Relation between the Hermitian inner product and the bilinear inner product===


In characteristic zero, we could use either the Hermitian inner product or the bilinear inner product (the latter works in general). Note that for a character <math>\chi</math> of a representation, we already have <math>\chi(g^{-1}) = \overline{\chi(g)}</math>, so ''restricted to characters'', the two inner products behave the same way. Thus, the two formulations are equivalent.
See [[inner product of functions#Relation between the definitions]]. The upshot is that both inner products are different but it does not matter if the input functions are characters.
 
For more on why <math>\chi(g^{-1}) = \overline{\chi(g)}</math>, combine [[element of finite order is semisimple and eigenvalues are roots of unity]] and the fact that for a root of unity, complex conjugation sends it to its inverse.
 
Note that the Hermitian inner product and bilinear form are ''not'' equivalent for ''arbitrary'' class functions. They cannot be, because one is Hermitian and positive-definite, while the other is bilinear.


==Consequences==
==Consequences==

Revision as of 03:15, 13 July 2011

This fact is related to: linear representation theory
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This article describes an orthogonality theorem. View a list of orthogonality theorems

Name

This result is known as the first orthogonality theorem, character orthogonality theorem or row orthogonality theorem.

Statement

Statement over complex numbers

Let G be a finite group and C denote the field of complex numbers. Let z¯ denote the complex conjugate of z. Then, if ρ1 and ρ2 are two inequivalent irreducible linear representations, and χ1 and χ2 are their characters, we have:

gGχ1(g)χ2(g)¯=0

and:

gGχ1(g)χ1(g)¯=|G|

Statement over complex numbers in terms of inner product of class functions

Consider the space of complex-valued functions GC. This is a C-vector space in a natural way, with basis being the indicator functions of elements of G. Consider the Hermitian inner product on this vector space given by:

f1,f2=1|G|gGf1(g)f2(g)¯

Then, the characters form an orthonormal set of functions with respect to this basis. In other words, if χ1,χ2 are the characters of inequivalent irreducible representations, we get:

χ1,χ1=1

and

χ1,χ2=0

Statement over general fields

Let G be a finite group and k a field whose characteristic does not divide the order of G. Let ρ1 and ρ2 be two inequivalent irreducible linear representations of G over k and let χ1 and χ2 denote their characters. Then, the following are true:

gGχ1(g)χ2(g1)=0

And:

gGχ1(g)χ1(g1)=d|G|

where d=1 if the field k is a splitting field for G (for instance, if k is sufficiently large for G, viz., contains all the mth roots of 1 where m is the exponent of G).

When k is not a splitting field, d is the number of irreducible constituents (with multiplicities) of χ1 when taken over a splitting field containing k.

Statement over general fields in terms of inner product of class functions

For functions f1,f2:Gk, define the following inner product:

f1,f2=1|G|gGf1(g)f2(g1)

Then, if χ1,χ2 are the characters of inequivalent irreducible representations, we get:

χ1,χ1=d

where d=1 if k is a splitting field and in general d is the number of irreducible constituents (with multiplicites) of χ1 when taken over a splitting field). Also:

χ1,χ2=0

Interpretation in characteristic zero and prime characteristic

In characteristic zero, both sides are being viewed as elements in a field of characteristic zero.

In prime characteristic, however, the inner product is taking values modulo the prime characteristic, hence is not actually an integer, whereas the right side (1, 0, or d) is an integer, which needs to be reduced modulo the prime to be interpreted on the other side.

Relation between the Hermitian inner product and the bilinear inner product

See inner product of functions#Relation between the definitions. The upshot is that both inner products are different but it does not matter if the input functions are characters.

Consequences