Zero-or-scalar lemma: Difference between revisions

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==Statement==
==Statement==


Let <math>G</math> be a [[finite group]] and <math>\phi</math> a nontrivial [[linear representation]] of <math>G</math>. Let <math>g \in G</math>, such that the size of the [[conjugacy class]] of <math>G</math> is relatively prime to the [[degree]] of <math>\phi</math>. Then, either <math>\phi(g)</math> is a scalar or <math>\chi(g) = 0</math>.
Let <math>G</math> be a [[finite group]] and <math>\phi</math> a nontrivial [[fact about::irreducible linear representation]] of <math>G</math>. Let <math>g \in G</math>, such that the size of the [[conjugacy class]] of <math>G</math> is relatively prime to the [[degree]] of <math>\phi</math>. Then, either <math>\phi(g)</math> is a scalar or <math>\chi(g) = 0</math>.


==Proof==
==Proof==

Revision as of 21:58, 22 February 2011

Statement

Let be a finite group and a nontrivial Irreducible linear representation (?) of . Let , such that the size of the conjugacy class of is relatively prime to the degree of . Then, either is a scalar or .

Proof

Let denote the conjugacy class of . We use the fact that the following is an algebraic integer:

Now, if and are relatively prime, then there exist integers and such that:

multiplying both sides by we get:

The left-hand-side is an algebraic integer, hence so is the right-hand-side. Thus is an algebraic integer.

We know that is a sum of roots of unity (not necessarily all distinct). Thus, every algebraic conjugate of is also a sum of roots of unity. In particular, this tells us that the norm of is either or .

Now if the norm is zero, then . If the norm is exactly 1, then all the roots of unity must be equal, and hence must be a scalar matrix.