Free quotient group admits a section: Difference between revisions
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Then, <math>N</math> is a [[fact about::complemented normal subgroup]] of <math>G</math>. In other words, there exists a [[retract]] <math>B</math> of <math>G</math> with [[normal complement]] <math>N</math>, i.e., <math>B</math> is a subgroup of <math>G</math> such that <math>G</math> is the [[fact about::internal semidirect product]] <math>N \rtimes B</math>. Explicitly, <math>N \cap B</math> is trivial and <math>NB = G</math>. | Then, <math>N</math> is a [[fact about::complemented normal subgroup]] of <math>G</math>. In other words, there exists a [[retract]] <math>B</math> of <math>G</math> with [[normal complement]] <math>N</math>, i.e., <math>B</math> is a subgroup of <math>G</math> such that <math>G</math> is the [[fact about::internal semidirect product]] <math>N \rtimes B</math>. Explicitly, <math>N \cap B</math> is trivial and <math>NB = G</math>. | ||
A normal subgroup <math>N</math> such that <math>G/N</math> is a free group is termed a [[fact about::free-quotient | A normal subgroup <math>N</math> such that <math>G/N</math> is a free group is termed a [[fact about::free-quotient subgroup]]. | ||
==Related facts== | ==Related facts== | ||
* [[Retract of free group is free on fewer generators]] | * [[Retract of free group is free on fewer generators]] | ||
Revision as of 20:24, 19 May 2010
Statement
Suppose is a normal subgroup of a group such that the quotient group is a Free group (?).
Then, is a Complemented normal subgroup (?) of . In other words, there exists a retract of with normal complement , i.e., is a subgroup of such that is the Internal semidirect product (?) . Explicitly, is trivial and .
A normal subgroup such that is a free group is termed a Free-quotient subgroup (?).