General affine group of degree one: Difference between revisions

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! Function !! Value !! Explanation
! Function !! Value !! Explanation
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| [[order of a group|order]] || <math>q(q - 1) = q^2 - q</math> || [[order of semidirect product is product of orders]]: The group is a semidirect product of the additive group of <math>\mathbb{F}_q</math>, which has order <math>q</math>, and the multiplicative group of <math>\mathbb{F}_q</math>, which has order <math>q - 1</math>.
| [[order of a group|order]] || <math>q(q - 1) = q^2 - q</math> || [[order of semidirect product is product of orders]]: The group is a semidirect product of the additive group of <math>\mathbb{F}_q</math>, which has order <math>q</math>, and the multiplicative group of <math>\mathbb{F}_q</math>, which has order <math>q - 1</math> (because it comprises all the non-identity elements).
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| [[exponent of a group|exponent]] || <math>p(q - 1)</math> || Non-identity elements in the additive group have order <math>p</math> and elements in the multiplicative group have order <math>q - 1</math>.
| [[exponent of a group|exponent]] || <math>p(q - 1)</math> || Non-identity elements in the additive group have order <math>p</math> and elements in the multiplicative group have order <math>q - 1</math>.
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| [[Frattini length]] || 1 || For <math>q > 2</math>, we can find two maximal subgroups of order <math>q - 1</math> with trivial intersection. Note that this also follows from it being a [[Frobenius group]].
| [[Frattini length]] || 1 || For <math>q > 2</math>, we can find two maximal subgroups of order <math>q - 1</math> with trivial intersection. Note that this also follows from it being a [[Frobenius group]].
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==Group properties==
==Group properties==



Revision as of 20:06, 20 May 2011

Definition

For a field

For a field F, the general affine group of degree one over F is defined as the general affine group over F of degree one. Equivalently, it is the external semidirect product of the additive group of F by the multiplicative group of F, where the latter acts naturally on the former by field multiplication.

For a finite number

Let p be a prime number and q=pr be a power of p. The general affine group or collineation group GA(1,q) is defined as follows. Let Fq denote the field with q elements. Then GA(1,q) is the semidirect product of the additive group of Fq with its multiplicative group.

Equivalently it is the general affine group of degree 1 over the field of q elements.

Particular cases

q (field size) p (underlying prime, field characteristic) GA(1,q) Order Second part of GAP ID
2 2 cyclic group:Z2 2 1
3 3 symmetric group:S3 6 1
4 2 alternating group:A4 12 3
5 5 general affine group:GA(1,5) 20 3
7 7 general affine group:GA(1,7) 42 1
8 2 general affine group:GA(1,8) 56 11
9 3 general affine group:GA(1,9) 72 39

Arithmetic functions

Below, q is the size of the field and p is the underlying prime (the characteristic of the field). We have q=pr where r is a positive integer.

Function Value Explanation
order q(q1)=q2q order of semidirect product is product of orders: The group is a semidirect product of the additive group of Fq, which has order q, and the multiplicative group of Fq, which has order q1 (because it comprises all the non-identity elements).
exponent p(q1) Non-identity elements in the additive group have order p and elements in the multiplicative group have order q1.
derived length 2 The derived subgroup is the additive group. The exception is the case q=2, where the group is abelian and has derived length 1.
Fitting length 2 The Fitting subgroup is the additive group of the field, and the quotient is an abelian group.
Frattini length 1 For q>2, we can find two maximal subgroups of order q1 with trivial intersection. Note that this also follows from it being a Frobenius group.

Group properties

Property Satisfied? Explanation Corollary properties satisfied/dissatisfied
Frobenius group Yes The additive subgroup Fq is a Frobenius kernel and the multiplicative subgroup is a Frobenius complement. (note: the case q=2 is an exception, where it fails to be a Frobenius group on account of the multiplicative group being trivial).
abelian group No Except the q=2 case, where we get cyclic group:Z2
nilpotent group No Except the q=2 case, where we get cyclic group:Z2
metabelian group Yes The derived subgroup is the additive group of the field (when q>2). Satisfies: solvable group
supersolvable group Sometimes The group is supersolvable if and only if the field is a prime field, i.e., if and only if q is a prime number rather than a strict prime power.