Sylow does not satisfy transfer condition: Difference between revisions

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* [[Hall does not satisfy transfer condition]]
* [[Hall does not satisfy transfer condition]]
 
* [[Normal Sylow satisfies transfer condition]]
* [[Normal Hall satisfies transfer condition]]
==Proof==
==Proof==



Revision as of 13:48, 28 September 2008

This article gives the statement, and possibly proof, of a subgroup property (i.e., Sylow subgroup) not satisfying a subgroup metaproperty (i.e., transfer condition).
View all subgroup metaproperty dissatisfactions | View all subgroup metaproperty satisfactions|Get help on looking up metaproperty (dis)satisfactions for subgroup properties
Get more facts about Sylow subgroup|Get more facts about transfer condition|

Statement

It is possible to have a finite group G, a Sylow subgroup H, and a subgroup K of G such that HK is not a Sylow subgroup of K.

Related facts

Proof

Hands-on proof

Property-theoretic proof

We know that the property of being a Sylow subgroup is transitive (a Sylow subgroup of a Sylow subgroup is Sylow). Thus, if the property of being Sylow satisfies the transfer condition, we have that the property of being a Sylow subgroup is intersection-closed, by the general fact Transitive and transfer condition implies intersection-closed.

On the other hand, an intersection of Sylow subgroups need not be Sylow.