A5 is simple: Difference between revisions

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==Related facts==
==Related facts==


* [[A5 is the simple non-Abelian group of smallest order]]
* A stronger statement about <math>A_5</math>: [[A5 is the simple non-Abelian group of smallest order]]


==Proof==
==Proof==


===Proof using sizes of conjugacy classes===
===Proof using sizes of conjugacy classes===
{{further|[[element structure of alternating group:A5]]}}


The conjugacy class sizes are <math>1, 12, 12, 20, 15</math>. A normal subgroup must contain the conjugacy class of size <math>1</math>, and one or more other conjugacy classes. Thus, the order of any normal subgroup must be a sum of some of these numbers, including the <math>1</math>. By [[Lagrange's theorem]], the order must also divide the order of the group. But no such sum among these numbers divides <math>60</math>, other than <math>1</math> and <math>60</math> themselves.
The conjugacy class sizes are <math>1, 12, 12, 20, 15</math>. A normal subgroup must contain the conjugacy class of size <math>1</math>, and one or more other conjugacy classes. Thus, the order of any normal subgroup must be a sum of some of these numbers, including the <math>1</math>. By [[Lagrange's theorem]], the order must also divide the order of the group. But no such sum among these numbers divides <math>60</math>, other than <math>1</math> and <math>60</math> themselves.


===Proof by listing subgroups===
===Proof by listing subgroups===
{{further|[[subgroup structure of alternating group:A5]]}}


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Latest revision as of 17:21, 23 October 2023

Statement

The alternating group of degree five (denoted ) is a simple group.

Related facts

Proof

Proof using sizes of conjugacy classes

Further information: element structure of alternating group:A5

The conjugacy class sizes are . A normal subgroup must contain the conjugacy class of size , and one or more other conjugacy classes. Thus, the order of any normal subgroup must be a sum of some of these numbers, including the . By Lagrange's theorem, the order must also divide the order of the group. But no such sum among these numbers divides , other than and themselves.

Proof by listing subgroups

Further information: subgroup structure of alternating group:A5

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