A5 is simple: Difference between revisions

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==Related facts==
==Related facts==


* [[A5 is the simple non-Abelian group of smallest order]]
* A stronger statement about <math>A_5</math>: [[A5 is the simple non-Abelian group of smallest order]]


==Proof==
==Proof==


===Proof using sizes of conjugacy classes===
===Proof using sizes of conjugacy classes===
{{further|[[element structure of alternating group:A5]]}}


The conjugacy class sizes are <math>1, 12, 12, 20, 15</math>. A normal subgroup must contain the conjugacy class of size <math>1</math>, and one or more other conjugacy classes. Thus, the order of any normal subgroup must be a sum of some of these numbers, including the <math>1</math>. By [[Lagrange's theorem]], the order must also divide the order of the group. But no such sum among these numbers divides <math>60</math>, other than <math>1</math> and <math>60</math> themselves.
The conjugacy class sizes are <math>1, 12, 12, 20, 15</math>. A normal subgroup must contain the conjugacy class of size <math>1</math>, and one or more other conjugacy classes. Thus, the order of any normal subgroup must be a sum of some of these numbers, including the <math>1</math>. By [[Lagrange's theorem]], the order must also divide the order of the group. But no such sum among these numbers divides <math>60</math>, other than <math>1</math> and <math>60</math> themselves.


===Proof by listing subgroups===
===Proof by listing subgroups===
{{further|[[subgroup structure of alternating group:A5]]}}


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Latest revision as of 17:21, 23 October 2023

Statement

The alternating group of degree five (denoted A5) is a simple group.

Related facts

Proof

Proof using sizes of conjugacy classes

Further information: element structure of alternating group:A5

The conjugacy class sizes are 1,12,12,20,15. A normal subgroup must contain the conjugacy class of size 1, and one or more other conjugacy classes. Thus, the order of any normal subgroup must be a sum of some of these numbers, including the 1. By Lagrange's theorem, the order must also divide the order of the group. But no such sum among these numbers divides 60, other than 1 and 60 themselves.

Proof by listing subgroups

Further information: subgroup structure of alternating group:A5

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