Frobenius conjecture on nth roots: Difference between revisions

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{{conjecture on|finite groups}}
{{conjecture|finite groups}}
==Statement==
==Statement==


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==Related facts==
==Related facts==


* [[Exactly n elements of order dividing n in a finite solvable group implies the elements form a subgroup]]: This is precisely the Frobenius conjecture in the case of [[finite solvable group]]s.
* [[Number of nth roots is a multiple of n]]
* [[Number of nth roots is a multiple of n]]
* [[Number of nth roots of any conjugacy class is a multiple of n]]
* [[Number of nth roots of any conjugacy class is a multiple of n]]
* [[At most n elements of order dividing n implies every finite subgroup is cyclic]]
* [[At most n elements of order dividing n implies every finite subgroup is cyclic]]

Latest revision as of 22:49, 11 November 2015

This article is about a conjecture in the following area in/related to group theory: finite groups. View all conjectures and open problems

Statement

Suppose is a finite group and is a natural number dividing the order of . Suppose the number of roots in , i.e., the number of elements such that , is exactly .

The Frobenius conjecture on nth roots states that in that case, that set of roots must be a subgroup of .

Related facts