Characteristic not implies derivation-invariant: Difference between revisions

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{{Lie subring property non-implication|
stronger = characteristic subring of a Lie ring|
weaker = derivation-invariant Lie subring}}
==Statement==
==Statement==


A [[fact about::characteristic subring of a Lie ring]] need not be a [[fact about::derivation-invariant Lie subring|derivation-invariant subring]].
A [[fact about::characteristic subring of a Lie ring;2| ]][[characteristic subring of a Lie ring]] need not be a [[fact about::derivation-invariant Lie subring;2| ]][[derivation-invariant Lie subring]].


==Related facts==
==Related facts==

Latest revision as of 15:12, 30 June 2013

This article gives the statement and possibly, proof, of a non-implication relation between two Lie subring properties. That is, it states that every Lie subring satisfying the first Lie subring property (i.e., characteristic subring of a Lie ring) need not satisfy the second Lie subring property (i.e., derivation-invariant Lie subring)
View a complete list of Lie subring property non-implications | View a complete list of Lie subring property implications
Get more facts about characteristic subring of a Lie ring|Get more facts about derivation-invariant Lie subring

Statement

A characteristic subring of a Lie ring need not be a derivation-invariant Lie subring.

Related facts

Similar facts

Opposite facts

Facts used

  1. Characteristic not implies fully invariant in finite abelian group

Proof

By fact (1), there exists a finite abelian group G with a characteristic subgroup H that is not fully invariant in G. Consider G as an abelian Lie ring, with trivial Lie bracket. Then, the automorphisms of G as a Lie ring are the same as the automorphisms as a group, so H is a characteristic subring of G. Further, the derivations of G as a Lie ring are precisely its endomorphisms as a group (because the Leibniz rule condition is vacuous). Thus, since H is not fully invariant by assumption, H is not derivation-invariant.