Sylow-unique prime divisor: Difference between revisions
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==Definition== | ==Definition== | ||
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We fix some notation. Let <math>p</math> be the prime divisor, <math>k</math> the exponent of <math>p</math> in <math>N</math>, and <math>m</math> the coprime part, viz <math>m = N/p^k</math>. | We fix some notation. Let <math>p</math> be the prime divisor, <math>k</math> the exponent of <math>p</math> in <math>N</math>, and <math>m</math> the coprime part, viz <math>m = N/p^k</math>. | ||
===Divisibility and congruence tests=== | ===Divisibility and congruence tests=== | ||
Let <math>n_p</math> denote the number of <math>p</math>-Sylow subgroups in the given group <math>G</math>. We know that the following hold: | Let <math>n_p</math> denote the number of <math>p</math>-Sylow subgroups in the given group <math>G</math>. We know that the following hold: | ||
* <math>n_p \equiv 1 \mod p</math> (the '''congruence condition''' in [[Sylow's theorem]]) | * [[congruence condition on Sylow numbers]]: <math>n_p \equiv 1 \mod p</math> (the '''congruence condition''' in [[Sylow's theorem]]) | ||
* <math>n_p</math> divides <math>m</math> (the '''divisibility condition''') | * [[divisibility condition on Sylow numbers]]: <math>n_p</math> divides <math>m</math> (the '''divisibility condition''') | ||
Note that both these conditions are purely in terms of <math>N</math> and <math>p</math> and do not depend on <math>G</math>. if the only solution to both these conditions is the solution <math>n_p = 1</math>, then clearly, <math>p</math> is Sylow-unique. | Note that both these conditions are purely in terms of <math>N</math> and <math>p</math> and do not depend on <math>G</math>. if the only solution to both these conditions is the solution <math>n_p = 1</math>, then clearly, <math>p</math> is Sylow-unique. | ||
Note, however, that while a unique solution to the congruence and divisibility conditions guarantees Sylow-uniqueness, the converse is not true. This is because there may be solutions to the congruence and divisibility conditions that do not get realized for actual groups. | Note, however, that while a unique solution to the congruence and divisibility conditions guarantees Sylow-uniqueness, the converse is not true. This is because there may be solutions to the congruence and divisibility conditions that do not get realized for actual groups. | ||
===Some special cases=== | |||
One special case where Sylow-uniqueness can be guaranteed is when the prime divisor is greater than the index <math>m</math>. In other words, if <math>N = p^km</math> where <math>m < p</math>, then the <math>p</math>-Sylow subgroup in any group of order <math>N</math> is unique. {{further|[[prime divisor greater than Sylow index is Sylow-unique]]}} | |||
Sometimes, close variants of this method guarantee that there exists some nontrivial normal Sylow subgroup, although we cannot ascertain ''which'' prime divisor it corresponds with. {{further|[[Order is product of Mersenne prime and one more implies normal Sylow subgroup]]}} | |||
==Presentations/talks on this== | |||
* [http://www.cmi.ac.in/~vipul/studenttalks/sylowconstraints.pdf Using Sylow theory in the classification of finite simple groups] |
Latest revision as of 14:41, 5 January 2009
This article defines a property of a prime divisor of an integer, one that is important/useful in the use of Sylow theory to study groups
BEWARE! This term is nonstandard and is being used locally within the wiki. [SHOW MORE]
History
This term is local to the wiki. To learn more about why this name was chosen for the term, and how it does not conflict with existing choice of terminology, refer the talk page
Definition
Symbol-free divisor
A prime divisor of a number is said to be Sylow-unique if for every group whose order is that number, there is a unique Sylow subgroup corresponding to that prime divisor.
Definition with symbols
A prime divisor of a number is said to be Sylow-unique if for any group of order , there is a unique -Sylow subgroup.
Relation with other properties
Stronger properties
- Sylow-direct prime divisor: A prime divisor such that the Sylow subgroup for that prime divisor is a direct factor of that group, for any group of the given order
Weaker properties
Testing for Sylow-uniqueness
We fix some notation. Let be the prime divisor, the exponent of in , and the coprime part, viz .
Divisibility and congruence tests
Let denote the number of -Sylow subgroups in the given group . We know that the following hold:
- congruence condition on Sylow numbers: (the congruence condition in Sylow's theorem)
- divisibility condition on Sylow numbers: divides (the divisibility condition)
Note that both these conditions are purely in terms of and and do not depend on . if the only solution to both these conditions is the solution , then clearly, is Sylow-unique.
Note, however, that while a unique solution to the congruence and divisibility conditions guarantees Sylow-uniqueness, the converse is not true. This is because there may be solutions to the congruence and divisibility conditions that do not get realized for actual groups.
Some special cases
One special case where Sylow-uniqueness can be guaranteed is when the prime divisor is greater than the index . In other words, if where , then the -Sylow subgroup in any group of order is unique. Further information: prime divisor greater than Sylow index is Sylow-unique
Sometimes, close variants of this method guarantee that there exists some nontrivial normal Sylow subgroup, although we cannot ascertain which prime divisor it corresponds with. Further information: Order is product of Mersenne prime and one more implies normal Sylow subgroup