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	<title>Subnormal-to-normal is normalizer-closed - Revision history</title>
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	<updated>2026-05-17T14:30:04Z</updated>
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		<id>https://groupprops.subwiki.org/w/index.php?title=Subnormal-to-normal_is_normalizer-closed&amp;diff=13728&amp;oldid=prev</id>
		<title>Vipul: New page: {{subgroup metaproperty satisfaction| property = subnormal-to-normal subgroup| metaproperty = normalizer-closed subgroup property}}  ==Statement==  Suppose &lt;math&gt;H&lt;/math&gt; is a [[subnormal-...</title>
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		<updated>2008-10-08T19:47:29Z</updated>

		<summary type="html">&lt;p&gt;New page: {{subgroup metaproperty satisfaction| property = subnormal-to-normal subgroup| metaproperty = normalizer-closed subgroup property}}  ==Statement==  Suppose &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is a [[subnormal-...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;{{subgroup metaproperty satisfaction|&lt;br /&gt;
property = subnormal-to-normal subgroup|&lt;br /&gt;
metaproperty = normalizer-closed subgroup property}}&lt;br /&gt;
&lt;br /&gt;
==Statement==&lt;br /&gt;
&lt;br /&gt;
Suppose &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is a [[subnormal-to-normal subgroup]] of a group &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;: either &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is normal in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is not subnormal in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;. Then, the [[normalizer]] of &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; is also a subnormal-to-normal subgroup of &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
==Related facts==&lt;br /&gt;
&lt;br /&gt;
* [[Intermediately subnormal-to-normal is normalizer-closed]]&lt;br /&gt;
* [[Intermediately normal-to-characteristic is normalizer-closed]]&lt;br /&gt;
* [[Automorph-conjugacy is normalizer-closed]]&lt;br /&gt;
* [[Intermediate automorph-conjugacy is normalizer-closed]]&lt;br /&gt;
&lt;br /&gt;
==Proof==&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Given&amp;#039;&amp;#039;&amp;#039;: A subnormal-to-normal subgroup &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; of a group &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;, with normalizer &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;To prove&amp;#039;&amp;#039;&amp;#039;: &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt; is also a subnormal-to-normal subgroup of &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Proof&amp;#039;&amp;#039;&amp;#039;: If &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt; is not subnormal in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; we are done. So, we need to prove that if &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt; is a subnormal subgroup of &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt; is normal in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
If &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt; is subnormal in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;, then, since &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is normal in &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is subnormal in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;. Since &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is subnormal-to-normal, &amp;lt;math&amp;gt;H&amp;lt;/math&amp;gt; is in fact normal in &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;, so &amp;lt;math&amp;gt;N_G(H) = G&amp;lt;/math&amp;gt;. Since every group is normal as a subgroup of itself, &amp;lt;math&amp;gt;N_G(H)&amp;lt;/math&amp;gt; is a normal subgroup of &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;.&lt;/div&gt;</summary>
		<author><name>Vipul</name></author>
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