Normality is not transitive for any pair of nontrivial quotient groups
From Groupprops
Statement
Suppose A and B are (possibly equal) nontrivial groups. Then, there exist groups
such that all the following conditions are satisfied:
- H is a normal subgroup of K and the quotient group K / H is isomorphic to A.
- K is a normal subgroup of G and the quotient group is isomorphic to B.
- H is not a normal subgroup of G.
Related facts
- Normality is not transitive
- Conjunction of normality with any nontrivial finite-direct product-closed property of groups is not transitive
- Normality is not transitive for any nontrivially satisfied extension-closed group property
- There exist subgroups of arbitrarily large subnormal depth
Proof
The construction is as follows. Let G be the wreath product of A and B for the regular group action of B. Let K be the subgroup AB, i.e., the normal subgroup that forms the base of the semidirect product, and let H be the subgroup of K where a particular coordinate is the identity element. (If we are thinking of AB as functions from B to A, then H can be taken as the subgroup comprising those functions that send the identity element of B to the identity element of A -- here, the particular coordinate becomes the coordinate corresponding to the identity element of B).
Thus, K is isomorphic to
. Then:
- H is normal in K and K / H is isomorphic to A: Fill this in later
- K is normal in G and G / K is isomorphic to B: Fill this in later
- H is not normal in G: The action of B on the coordinates in K = AB is transitive on the coordinates, so H is not preserved under this action.