No nontrivial abelian normal p-subgroup for some prime p implies every p-divisible normal subgroup is potentially characteristic
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This fact is related to: NPC conjecture
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Contents |
Statement
Statement with symbols
Suppose G is a group and p is a prime number such that G has no nontrivial abelian normal p-subgroup. Suppose H is a p-divisible normal subgroup of G: in other words, every element of H is the pth power of some element of H. Then, H is a potentially characteristic subgroup of G: there exists a group K containing G such that H is characteristic in K.
Related facts
Similar facts
- Finite NPC theorem
- Finite NIPC theorem
- No nontrivial abelian normal p-subgroup implies every normal subgroup is strongly image-potentially characteristic
Facts used
- Cayley's theorem
- Characteristicity is centralizer-closed
- Quotient group acts on abelian normal subgroup
- Characteristicity is transitive
Proof
Given: A finite group G, a prime p such that no element of G has order p. A normal subgroup H of G such that every element of H has a pth root.
To prove: There exists a group K containing G such that H is characteristic in K.
Proof:
- Let L = G / H. By fact (1), L is a subgroup of the symmetric group
, which in turn can be embedded in the automorphism group of a vector space over the field of p elements (the dimension of the vector space is | L | ). Thus, L has a faithful representation on a vector space V over the prime field of order p.
- Since L = G / H, a faithful representation of L on V gives a representation of G on V whose kernel is H. Let K be the semidirect product
for this action.
- V is characteristic in K: V is an abelian normal p-subgroup. By assumption,
has no nontrivial abelian normal p-subgroup, so V is the unique largest abelian normal p-subgroup. Hence, V is a characteristic subgroup of K.
- CK(V) is characteristic in K: This follows from the previous step and fact (2).
-
: Since V is abelian, the quotient group
acts on V (fact (3)); in particular, any two elements in the same coset of V have the same action by conjugation on V. Thus, the centralizer of V comprises those cosets of V for which the corresponding element of G fixes V. This is precisely the cosets of elements of H. Thus,
. Since the action is trivial,
.
- H is characteristic in
: H is a normal subgroup of
, on account of being a direct factor. Further, by the assumption that every element of H is a pth power, H is precisely the set of pth powers in
.
- H is characteristic in K: By steps (4) and (5),
is characteristic in K, and by step (6), H is characteristic in
. Thus, by fact (4), H is characteristic in K.
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