Abelian normal subgroup of core-free maximal subgroup is contranormal implies derived subgroup of whole group is monolith
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Statement
Suppose G is a primitive group, M is a core-free maximal subgroup of G (or, the stabilizer of a point for a faithful primitive group action of G), and A is an abelian normal subgroup of M that is a contranormal subgroup of G: G is generated by the conjugates of A in it. Then, the commutator subgroup [G,G] is the monolith of G, i.e., every nontrivial normal subgroup of G contains the commutator subgroup of G.
Facts used
Proof
Given: A group G, a core-free maximal subgroup M of G. An abelian normal subgroup A of M that is contranormal in G. A nontrivial normal subgroup N of G.
To prove: G / N is abelian.
Proof:
- MN = G: Since M is core-free and N is nontrivial normal, M does not contain N. Since M is maximal, MN = G.
- AN is normal in G: Clearly,
. Also, A is normal in M and N is normal in <mah>G</math>, so
. Thus,
, so NG(AN) = G by step (1).
- AN = G: By assumption, A is contranormal. Thus, the only normal subgroup of G containing A is G. So, by step (2), AN is normal in G.
-
is abelian: This follows from facts (1) and (2).
References
Textbook references
Facts about Abelian normal subgroup of core-free maximal subgroup is contranormal implies derived subgroup of whole group is monolithRDF feed
| Fact about | Primitive group +, Core-free maximal subgroup +, Abelian normal subgroup +, Contranormal subgroup +, and Commutator subgroup + |
| Page class | Fact + |
| Proved in | Book:Cohn (120, ?, ?) + |
| Referenced in | Book:Cohn (120, ?, ?) + |
| Stated in | Book:Cohn (120, ?, ?) + |
| Uses | Second isomorphism theorem +, and Abelianness is quotient-closed + |