Finitary symmetric group on countable set is subgroup-universal for finite groups

Statement
Let $$\Omega$$ be a countably infinite set and $$G := \operatorname{FSym}(\Omega)$$ be the finitary symmetric group on $$\Omega$$. Then, $$G$$ is subgroup-universal for finite groups. In other words, if $$H$$ is any finite group, $$H$$ is isomorphic to a subgroup of $$G$$.

Related facts

 * Free group on countable set is quotient-universal for finitely generated groups
 * Free group on two generators is SQ-universal

Facts used

 * 1) uses::Cayley's theorem: This states that every group embeds as a subgroup of the symmetric group on its underlying set.

Proof
The proof follows from fact (1), and the observation that the symmetric group on any finite set is isomorphic to some subgroup of $$G$$ -- namely, the subgroup comprising the permutations on a finite subset of $$\Omega$$ of the same cardinality.