Class-preserving not implies inner

Property-theoretic statement
The automorphism property of being a fact about::class-preserving automorphism does not imply the automorphism property of being an fact about::inner automorphism.

Verbal statement
We can find a group with a class-preserving automorphism (an automorphism sending every element to its conjugacy class) that is not inner.

Groups where the implication holds
There are certain important classes of groups where every class-preserving automorphism is inner. For instance, all the symmetric groups on finite sets have this property, as do certain groups arising in differential topology.

Stronger facts

 * Class-preserving not implies subgroup-conjugating

An equivalent fact
The existence of class-preserving automorphisms that are not inner is closely related to the following fact: conjugacy-closed normal not implies central factor. In other words, a conjugacy-closed normal subgroup (a normal subgroup that is also conjugacy-closed: elements in the subgroup that are conjugate in the whole group must be conjugate in the subgroup) need not be a central factor (a normal subgroup such that every inner automorphism of the whole group restricts to an inner automorphism of the subgroup).

Facts used

 * 1) Conjugacy-closed normal not implies central factor

Proof based on fact (1)
Note that:


 * A conjugacy-closed normal subgroup is a subgroup with the property that every inner automorphism of the whole group restricts to a class-preserving automorphism of the subgroup.
 * A central factor is a subgroup with the property that every inner automorphism of the whole group restricts to an inner automorphism of the subgroup.

Fact (1) states that there exist conjugacy-closed normal subgroups that are not central factors. This implies that these subgroups have class-preserving automorphisms that are not inner.

An infinite group example
One example of this is the finitary symmetric group on an infinite set: the group of all permutations that move only finitely many elements. Consider the automorphism on this group induced via conjugation by an infinitary permutation (a permutation that moves infinitely many elements). This automorphism sends every element to an element in the same conjugacy class, but is not an inner automorphism.

A finite group example
Constructing an example involving a finite group is somewhat more tricky. One construction is as follows. Consider the ring $$\mathbb{Z}/8\mathbb{Z}$$. Let $$A$$ be the additive group of this ring, and $$G$$ the multiplicative group of units. Let $$E$$ be the semidirect product $$A \rtimes G$$.

Now, we use three facts:


 * The stability group of $$1 \triangleleft A \triangleleft E$$ corresponds to the elements that are 1-cocycles for the action of $$G$$ on $$A$$
 * The elements in this stability group that come from inner automorphisms, are those that correspond to 1-coboundaries
 * The elements in this stability group that send every element to an element in the same conjugacy class, correspond to 1-cocycles such that for each element, it looks like a 1-coboundary. In other words, it is a 1-cocycle $$\varphi$$ for the action of $$G$$ on $$A$$, such that for every $$g \in G$$, there exists $$a \in A$$ (depending on $$g$$) such that we have:

$$\varphi(g) = g.a - a$$

To show that there is a class automorphism that is not inner, we basically need to construct such a 1-cocycle that is not a 1-coboundary. The construction, specifically, is:

$$\varphi(1) = \varphi(7) = 0, \varphi(3) = \varphi(5) = 4$$